This is a 2-part question: 1) Too much bunting in general 2) The 9th inning bunt. 1) Yes. Bunts work best with an element of surprise. There needs to be a reasonable expectation that the bunter can reach base. But, with the infield up, maybe even someone charging, a base hit expectation is lower. Giving up an out--that's what a sacrifice means--reduces the probability of scoring more than those already on base. Is scoring one (or two) enough to be decisive is the real question? Let's be blunt, the Twins scored three in the top of the first--Toronto scored two in first then tacked on Seven (!) more. Throwing away an out early doesn't make much sense. Which brings us to Part 2)--the bunt in the 9th. Does a sacrifice bunt make it easier to score two? Maybe marginally. BUT, here's the key, scoring two runs cannot win the game. Three are required. There is even more evidence. Tonight the bats are alive--it's already 9-7--there has been a lot of scoring, and more is to be expected. Runs have been scored in bunches! The lowest scored has been two in an inning (when there is scoring); Toronto is known to be a high-scoring team with HR power aplenty. Fact is, the Twins just plain don't know how many they need to score to win--except that that number is more than two runs. More evidence--LaTroy is pitching--a known entity, and he is wobbling! Two of Minnesota's "non-stars" got hits! This could be a huge inning! LaTroy is a strikeout/fly ball type pitcher, not the ground-ball (DP-inducing type). Plus, Robinson is tough to double-up anyway Finally, if Molitor truly believes Robinson can't hit LaTroy--he should pinch-hit! Hunter has XBH power, and two hits may not be needed to score two--or even three runs. A double, and two "productive outs" nets three runs. Preface the double with a sacrifice bunt (and the two outs)--Oh no!--only TWO runs score. Yikes!